Jamie Starke bio photo

Jamie Starke

I develop for my career, but I also develop for fun, and whenever I think it can solve a problem I'm having. This has lead me to create side projects, such as Rental Map and BusTimes, among others.

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This has been shamelessly borrowed from Chris Luce, as he showed them in one of my tutorials last week.

This example shows a Tic Tac Toe board, to see if there is a win in a board, or if it’s a cats game.

def printBoard(board):
    for i in range(0, len(board)):
        for j in range(0, len(board[0])):
            print board[i][j],
        print

def checkWinner(board):
    #check columns for winner
    for i in range(0, len(board)):
        if board[0][i] == "X" and board[1][i] == "X" and board[2][i] == "X":
            return "X"
        elif board[0][i] == "O" and board[1][i] == "O" and board[2][i] == "O":
            return "O"

    #check rows for winner
    for i in range(0, len(board[0])):
        if board[i][0] == "X" and board[i][1] == "X" and board[i][2] == "X":
            return "X"
        elif board[i][0] == "O" and board[i][1] == "O" and board[i][2] == "O":
            return "O"

    if board[0][0] == "X" and board[1][1] == "X" and board[2][2] == "X":
        return "X"
    elif board[0][0] == "O" and board[1][1] == "O" and board[2][2] == "O":
        return "O"
    if board[0][2] == "X" and board[1][1] == "X" and board[2][0] == "X":
        return "X"
    elif board[0][2] == "O" and board[1][1] == "O" and board[2][0] == "O":
        return "O"

board = []

board.append(['X','O','X'])
board.append(['X','X','O'])
board.append(['O','O','X'])

printBoard(board)

winner = checkWinner(board)

if winner == "X" or winner == "O":
    print "The winner is ", winner
else:
    print "Cat's game"

This example uses a 2 dimensional list, which you may find helpful to understand for your assignment.